Advertisements
Advertisements
Question
What is the current amplitude \[i_m\] for a pure inductor?
Options
\[i_m=\frac{v_m}{\omega L}\]
\[i_m=v_m\omega L\]
\[i_m=\frac{v_m\omega}{L}\]
\[i_m=\frac{\omega L}{v_m}\]
MCQ
Advertisements
Solution
The coefficient of the sine function in the integrated current is its amplitude. Hence, \[i_m=\frac{v_m}{\omega L}\].
shaalaa.com
Is there an error in this question or solution?
