Question

What is the completed-square form of \[x^2-6x+13\]?

Options

• \[(x-6)^2+13\]

• \[(x+3)^2+4\]

• \[(x-3)^2+4\]

• \[(x-3)^2-4\]

Answer 1

Add and subtract \[3^2\] to complete the square: \[x^2-6x+3^2-3^2+13\]. This simplifies to \[(x-3)^2+4\].