Question

What is the charge on the capacitor at time \[t\]?

Options

• \[q=Cv_m\sin\omega t\]

• \[q=Cv_m\cos\omega t\]

• \[q=\omega Cv_m\cos\omega t\]

• \[q=\frac{v_m}{C}\sin\omega t\]

Answer 1

Multiplying \[\frac{q}{C}=v_m\sin\omega t\] by \[C\] gives \[q=Cv_m\sin\omega t\]. The charge follows the applied voltage.