Question

What is the approximate voltage across the capacitor when \[I=0.755\,\mathrm{A}\] and \[X_C=212.2\,\Omega\]?

Options

• \[V_C=\frac{I}{X_C}\approx0.00356\,\mathrm{V}\]

• \[V_C=IX_C\approx151\,\mathrm{V}\]

• \[V_C=IX_C\approx160.3\,\mathrm{V}\]

• \[V_C=IX_C\approx220\,\mathrm{V}\]

Answer 1

Voltage across the capacitor is current times capacitive reactance. Multiplying \[0.755\,\mathrm{A}\] by \[212.2\,\Omega\] gives approximately \[160.3\,\mathrm{V}\].