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Question
What is the applied voltage at any instant when a capacitor is connected to an AC source?
Options
\[v=v_m\sin\omega t\]
\[v=v_m\sin 2\omega t\]
\[v=v_m\cos\omega t\]
\[v=\omega Cv_m\sin\omega t\]
MCQ
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Solution
The applied voltage varies sinusoidally with time as \[v=v_m\sin\omega t\]. Here, \[v_m\] is the peak voltage.
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