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Question
What is \[\frac{df}{dx}\] for \[f(x)=\sin(x^2)\]?
Options
\[2x\sin(x^2)\]
\[2x\cos(x^2)\]
\[\cos(x^2)\]
\[\sin(2x)\]
MCQ
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Solution
Differentiate the outer function \[\sin t\] to obtain \[\cos t\]. Since \[\frac{dt}{dx}=2x\], the derivative is \[2x\cos(x^2)\].
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