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Question
What is the function of:
(i) finely divided iron
(ii) Molybdenum in the above process
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Solution
(i) Finely divided iron acts as catalyst which alters the rate of reaction,
but itself does not undergo any chemical change.
(ii ) Molybdenum acts as promoter which increase the efficiency of
the catalyst.
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RELATED QUESTIONS
The following reactions are carried out:
A: \[\ce{Nitrogen + metal -> compound X}\]
B: \[\ce{X + water -> ammonia + another compound}\]
C: \[\ce{Ammonia + metal oxide -> metal + water + N2}\]
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