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Question
What do you observe when Cl2 is passed through potassium iodide (KI) solution.
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Solution
If in the solution of KI (Potassium iodide), we pass Chlorine gas (Cl2), then Chlorine will displace iodine from KI, and form Potassium Chloride (KCl), and liberates iodine,
\[\ce{Cl2 (aq) + 2 KI(aq) → 2 KCl (aq) + I2 (aq)}\]
When Iodine gas is passed into starch solution the solution becomes blue-black in colour.
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