Question

What conclusion can be drawn from part of given figure, if DC is the bisector of ∠ADB, CA ⊥ DA and CB ⊥ DB?

Answer 1

If DC is the bisector of ∠ADB, then ∠ADC = ∠BDC.

Also, CA ⊥ DA and CB ⊥ DB, then ∠CAD = 90° and ∠CBD = 90°