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Question
What alternating voltage is applied across the pure inductor of inductance \[L\]?
Options
\[v=v_m\sin\omega t\]
\[v=-v_m\sin\omega t\]
\[v=\omega L\sin\omega t\]
\[v=v_m\cos\omega t\]
MCQ
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Solution
The applied alternating voltage is \[v=v_m\sin\omega t\]. Here, \[v_m\] is the voltage amplitude.
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