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Question
What is the acceleration due to gravity on the top of Mount Everest? Mount Everest is the highest mountain peak of the world at the height of 8848 m. The value at sea level is 9.80 m s−2.
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Solution
Let g' be the acceleration due to gravity on Mount Everest.
\[\text { Then } g' = g\left( 1 - \frac{2h}{R} \right)\]
\[\text { here } h = 8848 m\]
\[ = 9 . 8\left( 1 - 0 . 00276 \right)\]
\[ = 9 . 0\left( 0 . 99724 \right)\]
\[ = 9 . 77 \ m/ s^2\]
∴ The acceleration due to gravity on the top of Mount Everest is 9.77 m/s2.
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