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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Verify that det(AB) = (det A)(det B) for A = [43-210723-5] and B = [133-240975] - Mathematics

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Question

Verify that det(AB) = (det A)(det B) for A = `[(4, 3, -2),(1, 0, 7),(2, 3, -5)]` and B = `[(1, 3, 3),(-2, 4, 0),(9, 7, 5)]`

Sum
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Solution

Given A = `[(4, 3, -2),(1, 0, 7),(2, 3, -5)]`

B = `[(1, 3, 3),(-2, 4, 0),(9, 7, 5)]`

AB = `[(4, 3, -2),(1, 0, 7),(2, 3, -5)] [(1, 3, 3),(-2, 4, 0),(9, 7, 5)]`

= `[(4 - 6 - 18, 12 + 12 - 14, 12 + 0 - 10),(1 - 0 + 63,3 +0 + 49, 3 + 0 + 35),(2 - 6 - 45, 6 + 12 - 35, 6 + 0 - 25)]`

= `[(-20, 10, 2),(64, 52, 38),(-49, -1, -19)]`

det(AB) = |AB|

= `|(-20, 10, 2),(64, 52, 38),(-49, - 17, -19)|`

= `2 xx 2 |(-10, 5, 1),(32, 26, 19),(-49, -17, -19)|`

= `4|(-10, 5, 1),(32, 26, 19),(-17, -9, 0)|  "R"_3 -> "R"_3 + "R"_2`

= 4 [– 10 (0 – 9 × 19) – 5(0 + 17 × 19) + 1(32 × 9 + 17 × 26)]

= 4[1710 – 5 × 323 + 288 + 442]

= 4[1710 – 1615 + 730]

= 4[2440 – 1615]

= 4 × 825

det (AB) = 3300 .......(1)

A = `[(4, 3, -2),(1, 0, 7),(2, 3, -5)]`

|A| = `[(4, 3, -2),(1, 0, 7),(2, 3, -5)]`

= 4(0 – 21) – 3(– 5 – 14) – 2(3 – 0)

= – 84 – 3 × – 19 – 6

= – 84 + 57 – 6

= – 90 + 57

det A = – 33 .......(2)

B = `[(1, 3, 3),(-2, 4, 0),(9, 7, 5)]`

|B| = `|(1, 3, 3),(-2, 4, 0),(9, 7, 5)|`

= 1(20 – 0) – 3(– 10 – 0) + 3(– 14 – 36)

= 20 + 30 + 3 × – 50

= 50 – 150

det A = – 100 .......(3)

From equations (2) and (3)

(det A)(det B) = – 33 × – 100

(detA)(det B) = 3300 ........(4)

From equations (1) and (4), we have

det(AB) = (det A)(det B)

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Chapter 7: Matrices and Determinants - Exercise 7.2 [Page 30]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 7 Matrices and Determinants
Exercise 7.2 | Q 20 | Page 30

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