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Question
Verify that A2 = I when A = `[(0, 1, -1),(4, -3, 4),(3, -3, 4)]`
Sum
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Solution
We have, A = `[(0, 1, -1),(4, -3, 4),(3, -3, 4)]`
∴ A2 = `[(0, 1, -1),(4, -3, 4),(3, -3, 4)] * [(0, 1, -1),(4, -3, 4),(3, -3, 4)]`
= `[(0 + 4 - 3, 0 - 3 + 3, 0 + 4 - 4),(0 - 12 + 12, 4 + 9 - 12, -4 - 12 +16),(0 - 12 + 12, 3 + 9 - 12, -3 - 12 + 16)]`
= `[(1,0, 0),(0, 1, 0),(0, 0, 1)]`
= I
Hence proved.
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