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Question
Using trigonometric tables, find the approximate value of sec 23° 20'.
Sum
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Solution
Given: `sec 23^circ 20' = 1/(cos 23^circ 20')`
Step-wise calculation:
1. From trigonometric tables, cos 23°20' ≈ 0.91814.
2. Therefore, `sec 23^circ 20' = 1/0.91814`
sec 23°20' ≈ 1.08905
sec 23°20' ≈ 1.0891
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Chapter 19: Trigonometric tables - Exercise 19A [Page 431]
