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Maharashtra State BoardSSC (English Medium) 6th Standard

Using the figures given below, frame problems based on profit percent or loss percent.​ Seeds worth ₹ 20500, labour ₹ 9700, chemicals and fertilizers ₹ 5600, selling price ₹ 28640.

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Question

Using the figures given below, frame problems based on profit percent or loss percent.

Seeds worth ₹ 20500, labour ₹ 9700, chemicals and fertilizers ₹ 5600, selling price ₹ 28640.

Sum
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Solution

Problem: A farmer purchased some seeds worth Rs 20500 for his field. He paid Rs 9700 on labour besides Rs 5600 on chemicals and fertilisers. If the selling price of his produce was worth Rs 28640, what was the percentage of his profit or loss?

Cost price of seeds = ₹ 20500

Money spent on labour = ₹ 9700

Money spent on chemicals and fertilizers = ₹ 5600

Total expenses = cost of seeds + labour charges + money

spent on chemicals and fertilizers

= 20500 + 9700 + 5600

= Rs 35800

That is, total cost price is Rs 35800.

Selling price of the produce = Rs 28640

Since selling price is less than the total cost price, so there is a loss.

Loss = Total cost price − selling price

= 35800 − 28640

= Rs 7160

Let x % be the farmer's loss. Then, 

`"x"/100 = "loss"/"Total cost price"`

`=> "x"/100 = 7160/35800`

`=> "x"/100 xx 100 = 7160/35800 xx 100`

⇒ x = 20 

∴ The farmer suffered a loss of 20% in this transaction. 

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Chapter 13: Profit – Loss - Practice Set 34 [Page 72]

APPEARS IN

Balbharati Mathematics [English] Standard 6 Maharashtra State Board
Chapter 13 Profit – Loss
Practice Set 34 | Q 6 | Page 72
Balbharati Mathematics Integrated [English] Standard 6 Maharashtra State Board
Chapter 13 Profit-Loss
Practice Set 34 | Q 6. | Page 67

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