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Question
Using Remainder Theorem, find the remainder when $$f(x) = x^3 - 2x^2 - 5x + 6$$ is divided by $$(x + 2)$$.
Theorem
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Solution
Since the divisor is $$x + 3 = x - (-3)$$, the remainder is $$f(-3)$$.
$$f(-3) = (-3)^3 - 2(-3)^2 - 5(-3) + 6$$
$$= -8 - 8 + 10 + 6$$
$$= 0$$
Hence, the remainder is $$0$$.
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