English

Using prime factorisation, find the HCF and LCM of 8, 9, 25.

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Question

Using prime factorisation, find the HCF and LCM of 8, 9, 25.

Sum
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Solution

8 = 2 × 2 × 2 = 23

9 = 3 × 3 = 32

25 = 5 × 5 = 52

HCF = product of smallest power of each common prime factor in the numbers = 1

LCM = product of greatest power of each prime factor involved in the numbers

= 23 × 32 × 52

= 1800

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Chapter 1: Real Numbers - EXERCISE 1B [Page 17]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 1 Real Numbers
EXERCISE 1B | Q 5. (i) | Page 17
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