Question

Using Ohm’s law \[V = IR\] in \[P = IV\], which expression for power in a resistor results?

Options

• \[P = \frac{I^2}{R}\]

• \[P = I^2R\]

• \[P = IR^2\]

• \[P = \frac{R}{I^2}\]

Answer 1

Substituting \[V = IR\] into \[P = IV\] gives \[P = I(IR)\]. Therefore, the power dissipated in the resistor is \[P = I^2R\].