Advertisements
Advertisements
Question
Using identity, find the value of (100.1)2
Advertisements
Solution
(100.1)2 = (100 + 0.1)2
Substituting a = 100 and b = 0.1 in
(a + b)2 = a2 + 2ab + b2, we have
(100 + 0.1)2 = (100)2 + 2(100)(0.1) + (0.1)2
(100.1)2 = 10000 + 20 + 0.01
(100.1)2 = 10020.01
APPEARS IN
RELATED QUESTIONS
Find the following squares by suing the identities.
`(2/3 m + 3/4 n)^2`
Using identities, evaluate 1.05 × 9.5
Expand `("a"/2+"b"/3)^2`
Use the formula to multiply the following.
`(x/5+6)(x/5-6)`
If a + b = 10 and ab = 18, find the value of a2 + b2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x3 + 2abx2 + b2x
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
`9x^2 + 2xy + y^2/9`
Verify the following:
(a + b)(a + b)(a + b) = a3 + 3a2b + 3ab2 + b3
Find the length of the side of the given square if area of the square is 625 square units and then find the value of x.
