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Using factor theorem, show that (x – 3) is a factor of [(x^{3} + x^{2} – 17x + 15)].

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Question

Using factor theorem, show that (x – 3) is a factor of \[(x^{3} + x^{2} - 17x + 15)\].

Theorem
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Solution

Given: \[f(x) = (x^{3} + x^{2} - 17x + 15)\]

To prove: (x – 3) is a factor and the complete factorisation of f(x)

Proof:

By the Factor Theorem: Let $$f(x)$$ be a given polynomial and $$\alpha$$ be a given real number.

Then, $$(x - \alpha)$$ is a factor of $$f(x) \Leftrightarrow f(\alpha) = 0$$.

For let $$f_1(x) = x^3 + x^2 - 17x + 15$$.

$$f_1(3) = 27 + 9 - 51 + 15 = 0$$.

Therefore, $$(x - 3)$$ is a factor of $$f_1(x)$$.

Hence proved.

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Chapter 8: Remainder Theorem and Factor Theorem - EXERCISE 8B [Page 127]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 8 Remainder Theorem and Factor Theorem
EXERCISE 8B | Q 1. (i) | Page 127
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