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Using \(\cos^2 x = \frac{1+\cos 2x}{2}\), which expression is equivalent to \(\int \cos^2 x\,dx\)?

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Question

Using \(\cos^2 x = \frac{1+\cos 2x}{2}\), which expression is equivalent to \(\int \cos^2 x\,dx\)?

Options

  • \(\frac{1}{2}\int(1+\cos 2x)\,dx\)

  • \(\int(1+\cos 2x)\,dx\)

  • \(2\int(1+\cos 2x)\,dx\)

  • \(\frac{1}{2}\int(1-\cos 2x)\,dx\)

MCQ
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Solution

Substituting \(\cos^2 x = \frac{1+\cos 2x}{2}\) places the factor \(\frac{1}{2}\) outside the integral. Thus, the integral becomes \(\frac{1}{2}\int(1+\cos 2x)\,dx\).

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