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Question
Using \(\cos^2 x = \frac{1+\cos 2x}{2}\), which expression is equivalent to \(\int \cos^2 x\,dx\)?
Options
\(\frac{1}{2}\int(1+\cos 2x)\,dx\)
\(\int(1+\cos 2x)\,dx\)
\(2\int(1+\cos 2x)\,dx\)
\(\frac{1}{2}\int(1-\cos 2x)\,dx\)
MCQ
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Solution
Substituting \(\cos^2 x = \frac{1+\cos 2x}{2}\) places the factor \(\frac{1}{2}\) outside the integral. Thus, the integral becomes \(\frac{1}{2}\int(1+\cos 2x)\,dx\).
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