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Question
Use Boolean algebra to find the most simplified SOP expression for F=ABD+CD+ ACD+ABC+ABCD
Options
F = ABD+ABC+CD
F= CD+AD
F = BC+AB
F= AC+AD
MCQ
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Solution
F = ABD+ABC+CD
Explanation:
Since [CD+ACD=CD] and [CD+ABCD=CD], the expression becomes [F=ABD+CD+ABC].
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