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Two satellites A and B are revolving round a planet. Their periods of revolution are 1 hour and 8 hour respectively. The radius of orbit of satellite B is 4 × 104 km.

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Question

Answer the following question in detail.

Two satellites A and B are revolving round a planet. Their periods of revolution are 1 hour and 8 hour respectively. The radius of orbit of satellite B is 4 × 104 km. Find radius of orbit of satellite A.

Sum
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Solution

Given: TA = 1 hour, TB = 8 hour, rB = 4 × 104 km

To find: Radius of orbit of satellite A (rA)

Formula: T = `2pi sqrt("r"^3/"GM")`

Calculation: From formula,

`"T"^2 = (4pi^2"r"^3)/"GM"`

∴ `"T"^2 prop "r"^3     ......(because (4pi^2"r"^3)/"GM" = "constant for a planet")`

∴ `(("T"_"A")/("T"_"B"))^2 = (("r"_"A")/("r"_"B"))^3`

∴ `(1/8)^2 = ("r"_"A"/(4 xx 10^4))^3`

∴ `"r"_"A"^3 = 1/(8)^2 xx (4 xx 10^4)^3`

∴ `"r"_"A"^3 = 10^12`

∴ `"r"_"A" = 1 xx 10^4` km

Radius of orbit of satellite A will be 1 × 104 km. 

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Chapter 5: Gravitation - Exercises [Page 98]

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Balbharati Physics [English] Standard 11 Maharashtra State Board
Chapter 5 Gravitation
Exercises | Q 4. (iv) | Page 98

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