Advertisements
Advertisements
Question
Two lines of regression are 10x + 3y − 62 = 0 and 6x + 5y − 50 = 0. Identify the regression of x on y. Hence find `bar x, bar y` and r.
Advertisements
Solution
Given, two lines of regression are
10x + 3y – 62 = 0
i.e., 10x + 3y = 62 …(i)
and 6x + 5y – 50 = 0
i.e., 6x + 5y = 50 …(ii)
By (i) × 5 - (ii) × 3, we get
50x + 15y = 310
18x + 15y = 150
- - -
32x = 160
∴ x = 5
Substituting x = 5 in (i) we get,
10(5) + 3y = 62
∴ 50 + 3y = 62
∴ 3y = 62 - 50 = 12
∴ y = 4
Since the point of intersection of two regression lines is `(bar x, bar y)`,
`bar x = 5 and bar y = 4`
Now,
Let 10x + 3y - 62 = 0 be the regression equation of X on Y.
∴ The equation becomes 10x = –3y + 62
i.e., 10X = –3Y + 62
i.e., X = `- 3/10 "Y" + 62/10`
Comparing it with X = bXY Y + a, we get
∴ `"b"_"XY" = - 3/10`
Now, other equation 6x + 5y – 50 = 0 be the regression equation of Y on X.
∴ The equation becomes 5y = – 6x + 50
i.e., 5Y = – 6X + 50
i.e., Y = `- 6/5 "x" + 50/5`
Comparing it with Y = bYX X + a', we get
`"b"_"YX" = - 6/5`
Now, `"b"_"YX" * "b"_"XY" = (- 3/10)(- 6/5) = 9/25`
i.e., bXY . bYX < 1
∴ Assumption of regression equations is true.
∴ r = `+-sqrt("b"_"XY" * "b"_"YX") = +-sqrt(9/25) = +- 3/5`
Since bYX and bXY both are negative,
r is negative.
∴ r = `- 3/5 = - 0.6`
APPEARS IN
RELATED QUESTIONS
Bring out the inconsistency in the following:
bYX = 2.6 and bXY = `1/2.6`
For certain bivariate data the following information is available.
| X | Y | |
| Mean | 13 | 17 |
| S.D. | 3 | 2 |
Correlation coefficient between x and y is 0.6. estimate x when y = 15 and estimate y when x = 10.
In a partially destroyed laboratory record of an analysis of regression data, the following data are legible:
Variance of X = 9
Regression equations:
8x − 10y + 66 = 0
and 40x − 18y = 214.
Find on the basis of above information
- The mean values of X and Y.
- Correlation coefficient between X and Y.
- Standard deviation of Y.
For 50 students of a class, the regression equation of marks in statistics (X) on the marks in accountancy (Y) is 3y − 5x + 180 = 0. The variance of marks in statistics is `(9/16)^"th"` of the variance of marks in accountancy. Find the correlation coefficient between marks in two subjects.
For bivariate data, the regression coefficient of Y on X is 0.4 and the regression coefficient of X on Y is 0.9. Find the value of the variance of Y if the variance of X is 9.
The equations of two regression lines are
2x + 3y − 6 = 0
and 3x + 2y − 12 = 0 Find
- Correlation coefficient
- `sigma_"X"/sigma_"Y"`
For a bivariate data, `bar x = 53`, `bar y = 28`, byx = −1.5 and bxy = −0.2. Estimate y when x = 50.
In a partially destroyed record, the following data are available: variance of X = 25, Regression equation of Y on X is 5y − x = 22 and regression equation of X on Y is 64x − 45y = 22 Find
- Mean values of X and Y
- Standard deviation of Y
- Coefficient of correlation between X and Y.
Regression equations of two series are 2x − y − 15 = 0 and 3x − 4y + 25 = 0. Find `bar x, bar y` and regression coefficients. Also find coefficients of correlation. [Given `sqrt0.375` = 0.61]
The two regression lines between height (X) in inches and weight (Y) in kgs of girls are,
4y − 15x + 500 = 0
and 20x − 3y − 900 = 0
Find the mean height and weight of the group. Also, estimate the weight of a girl whose height is 70 inches.
The following results were obtained from records of age (X) and systolic blood pressure (Y) of a group of 10 men.
| X | Y | |
| Mean | 50 | 140 |
| Variance | 150 | 165 |
and `sum (x_i - bar x)(y_i - bar y) = 1120`. Find the prediction of blood pressure of a man of age 40 years.
If bYX = − 0.6 and bXY = − 0.216, then find correlation coefficient between X and Y. Comment on it.
Choose the correct alternative:
If for a bivariate data, bYX = – 1.2 and bXY = – 0.3, then r = ______
Choose the correct alternative:
If byx < 0 and bxy < 0, then r is ______
Choose the correct alternative:
bxy and byx are ______
Choose the correct alternative:
If r = 0.5, σx = 3, `σ_"y"^2` = 16, then byx = ______
State whether the following statement is True or False:
If byx = 1.5 and bxy = `1/3` then r = `1/2`, the given data is consistent
State whether the following statement is True or False:
If u = x – a and v = y – b then bxy = buv
If u = `(x - "a")/"c"` and v = `(y - "b")/"d"`, then bxy = ______
If the sign of the correlation coefficient is negative, then the sign of the slope of the respective regression line is ______
byx is the ______ of regression line of y on x
Given the following information about the production and demand of a commodity.
Obtain the two regression lines:
| Production (X) |
Demand (Y) |
|
| Mean | 85 | 90 |
| Variance | 25 | 36 |
Coefficient of correlation between X and Y is 0.6. Also estimate the demand when the production is 100 units.
| x | y | `x - barx` | `y - bary` | `(x - barx)(y - bary)` | `(x - barx)^2` | `(y - bary)^2` |
| 1 | 5 | – 2 | – 4 | 8 | 4 | 16 |
| 2 | 7 | – 1 | – 2 | `square` | 1 | 4 |
| 3 | 9 | 0 | 0 | 0 | 0 | 0 |
| 4 | 11 | 1 | 2 | 2 | 4 | 4 |
| 5 | 13 | 2 | 4 | 8 | 1 | 16 |
| Total = 15 | Total = 45 | Total = 0 | Total = 0 | Total = `square` | Total = 10 | Total = 40 |
Mean of x = `barx = square`
Mean of y = `bary = square`
bxy = `square/square`
byx = `square/square`
Regression equation of x on y is `(x - barx) = "b"_(xy) (y - bary)`
∴ Regression equation x on y is `square`
Regression equation of y on x is `(y - bary) = "b"_(yx) (x - barx)`
∴ Regression equation of y on x is `square`
Mean of x = 25
Mean of y = 20
`sigma_x` = 4
`sigma_y` = 3
r = 0.5
byx = `square`
bxy = `square`
when x = 10,
`y - square = square (10 - square)`
∴ y = `square`
bXY . bYX = ______.
If byx > 1 then bxy is _______.
