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Question
Two identical cubes each of volume 64 cm3 are joined together end to end. What is the surface area of the resulting cuboid?
Sum
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Solution

Let the side of one cube = a
Surfaces area of resulting cuboid = 2(Total surface area of a cube) – 2(area of single surface)
We know that,
Total surface area of cube = 6a2, where a = side of cube
⇒ Surfaces area of resulting cuboid = 2(6a2) – 2(a2) = 10a2
Also,
According to the question,
Volume of cube = 64 cm3
Volume of cube = a3
64 = a3
a = 4 cm
Therefore, surface area of resulting cuboid = 10a2 = 10(4)2 = 160 cm2
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