Advertisements
Advertisements
Question
Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is less than or equal to 12.
Sum
Advertisements
Solution
The number of possible outcomes = 6 × 6 = 36
All the outcomes are favourable to the event E = sum of two numbers ≤ 12
Hence, `P(E) = (n(E))/(n(S)) = 36/36 = 1`
shaalaa.com
Is there an error in this question or solution?
Chapter 25: Probability - TEST YOURSELF [Page 407]
