Advertisements
Advertisements
Question
Two cross roads, each of width 10 m, cut at right angles through the centre of a rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area of the roads. Also find the area of the park excluding cross roads. Give the answer in hectares.
Advertisements
Solution

Length (l) of park = 700 m
Breadth (b) of park = 300 m
Area of park = 700 × 300 = 210000 m2
Length of road PQRS = 700 m
Length of road ABCD = 300 m
Width of each road = 10 m
Area of the roads = ar (PQRS) + ar (ABCD) − ar (KLMN)
= (700 × 10) + (300 × 10) − (10 × 10)
= 7000 + 3000 − 100
= 10000 − 100 = 9900 m2 = 0.99 hectare
Area of park excluding roads = 210000 − 9900 = 200100 m2 = 20.01 hectare
RELATED QUESTIONS
150 kg 200 g + 55 kg 750 g = ______ kg ______ g
450 ml × 5 = ……. l …… ml
Compare and put > or < or = in the following:
88 cm `square` 8 m 8 cm
Put ✓ mark in the circles which adds upto the given measure
7 kg 400 g = ________ g
9500 mg = _______ g _______ mg
_________ is the smallest metric measure of capacity
7 kl 30 l = ________ l
1 km2 = ______ m2.
5 hectare = 500 m2
