Advertisements
Advertisements
Question
Two cross roads, each of width 10 m, cut at right angles through the centre of a rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area of the roads. Also find the area of the park excluding cross roads. Give the answer in hectares.
Advertisements
Solution

Length (l) of park = 700 m
Breadth (b) of park = 300 m
Area of park = 700 × 300 = 210000 m2
Length of road PQRS = 700 m
Length of road ABCD = 300 m
Width of each road = 10 m
Area of the roads = ar (PQRS) + ar (ABCD) − ar (KLMN)
= (700 × 10) + (300 × 10) − (10 × 10)
= 7000 + 3000 − 100
= 10000 − 100 = 9900 m2 = 0.99 hectare
Area of park excluding roads = 210000 − 9900 = 200100 m2 = 20.01 hectare
RELATED QUESTIONS
250 ml + `1/2` l = ……………… l
Pugazhenthi ate 100 g of nuts which is equal to 0.1 kg
Karkuzhali's bag 1 kg 250 g and Poongkodi's bag 2 kg 750 g. The total weight of their bags 4 kg
Convert into higher units:
13000 mm (km, m, cm)
Convert into lower units:
12 kg (g, mg)
1006 g is equal to _________
7000 m is 7 km
Match the following
| Column A | Column B |
| (i) 4500 ml | 6 l 500 ml |
| (ii) 3250 ml | 8 l 200 ml |
| (iii) 6500 ml | 7 l 50 ml |
| (iv) 8200 ml | 4 l 500 ml |
| (v) 7050 ml | 3 l 250 ml |
1 hectare = ______ m2.
1 km2 = ______ m2.
