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Question
Two charged particles with charge 2.0 × 10−8 C each are joined by an insulating string of length 1 m and the system is kept on a smooth horizontal table. Find the tension in the string.
Short/Brief Note
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Solution
Given:
Magnitude of the charges, q = 2.0 × 10−8 C
Separation between the charges, r = 1 m
The tension in the string will be same as the electrostatic force between the charged particles.
So,
\[T = F\]
By Coulomb's Law,
\[F = \frac{1}{4\pi \epsilon_0}\frac{q^2}{r^2}\]
\[\Rightarrow T = \frac{9 \times {10}^9 \times \left( 2 . 0 \times {10}^{- 8} \right)^2}{1^2}\]
\[ = 3 . 6 \times {10}^{- 6}\] N
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