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Karnataka Board PUCPUC Science Class 11

Two Charged Particles with Charge 2.0 × 10−8 C Each Are Joined by an Insulating String of Length 1 M and the System is Kept on a Smooth Horizontal Table. Find the Tension in the String. - Physics

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Question

Two charged particles with charge 2.0 × 10−8 C each are joined by an insulating string of length 1 m and the system is kept on a smooth horizontal table. Find the tension in the string.

Short/Brief Note
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Solution

Given:
Magnitude of the charges, q =  2.0 × 10−8 C
Separation between the charges, r = 1 m
The tension in the string will be same as the electrostatic force between the charged particles.
So,  

\[T = F\]

By Coulomb's Law,         

\[F = \frac{1}{4\pi \epsilon_0}\frac{q^2}{r^2}\]

\[\Rightarrow T = \frac{9 \times {10}^9 \times \left( 2 . 0 \times {10}^{- 8} \right)^2}{1^2}\] 

\[                   = 3 . 6 \times  {10}^{- 6}\] N

 
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Chapter 7: Electric Field and Potential - Exercises [Page 121]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 7 Electric Field and Potential
Exercises | Q 21 | Page 121
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