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Question
Two charged particles are placed 1.0 cm apart. What is the minimum possible magnitude of the electric force acting on each charge?
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Solution
We know that minimum charge on a body (q) = charge on an electron
⇒ q = 1.6 × 10−19 C
Given:
Separation between the charges, r = 1 cm = 10-2 m
By Coulomb's Law, force,
\[\Rightarrow F = \frac{9 \times {10}^9 \times \left( 1 . 6 \times {10}^{- 19} \right)^2}{\left( {10}^{- 2} \right)^2}\]
\[ \Rightarrow F = 2 . 3 \times {10}^{- 24} N\]
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