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Karnataka Board PUCPUC Science Class 11

Estimate the Number of Electrons in 100 G of Water. How Much is the Total Negative Charge on These Electrons? - Physics

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Question

Estimate the number of electrons in 100 g of water. How much is the total negative charge on these electrons?

Short/Brief Note
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Solution

Molecular mass of water= 18 g
Number of molecules in 18 g of H2O = Avogadro's number 
                                                            = 6.023 × 1023
Number of electrons in 1 molecule of H2O = (2 × 1) + 8 = 10
Number of electrons in 6.023 × 1023 molecules of H2O = 6.023 × 1024
That is, number of electrons in 18 g of H2O = 6.023 × 1024
So, number of electrons in 100 g of H2O = \[\frac{6 . 023 \times {10}^{24}}{18} \times 100\]

                                                                 = 3.34 × 1025
         ∴ Total charge = 3.34 × 1025 × 1.6 × 10−19
                                 = 5.34 × 106 C

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Chapter 7: Electric Field and Potential - Exercises [Page 121]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 7 Electric Field and Potential
Exercises | Q 9 | Page 121
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