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Question
Two APs have the same common difference. The difference between their 100th term is 100, what is the difference between their 1000th terms?
Sum
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Solution
Let for the 1st AP, the first term = a and common difference = d
T100 = a + 99d
And for the 2nd AP, the first term = a and common difference = d
T100 = a + 99d
According to the condition
T100 - T100 = 100
a + 99d - (a + 99d) = 100
a - a = 100
Let T1000 - T1000 = x
a + 999d - (a + 999d) = x
a - a = x
x = 100
The difference between the 1000th terms is 100.
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