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Question
Three unbiased coins are tossed simultaneously. Find the probability of getting:
- at least one head
- exactly one tail
- two heads and one tail
- at most two heads
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Solution
Total Possible Outcomes: When three unbiased coins are tossed simultaneously, the sample space is:
\[ S = {\text{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}} \]
\[ n(S) = 8 \]
(i) At least one head: All outcomes except TTT have at least one head.
Favourable outcomes: `({\text{HHH, HHT, HTH, THH, HTT, THT, TTH}})`
(7 outcomes)
\[ P(\text{at least one head}) = \dfrac{7}{8} \]
(ii) Exactly one tail: Favourable outcomes: `({\text{HHT, HTH, THH}} )`
(3 outcomes)
\[ P(\text{exactly one tail}) = \dfrac{3}{8} \]
(iii) Two heads and one tail: Favourable outcomes: `({\text{HHT, HTH, THH}})`
(3 outcomes)
\[ P(\text{two heads and one tail}) = \dfrac{3}{8} \]
(iv) At most two heads: Possible outcomes can have 0, 1 or 2 heads (all outcomes except HHH).
Favourable outcomes: `({\text{HHT, HTH, THH, HTT, THT, TTH, TTT}})`
(7 outcomes)
\[ P(\text{at most two heads}) = \dfrac{7}{8} \]
