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Three Digit Numbers Are Formed Using the Digits 0, 2, 4, 6, 8. a Number is Chosen at Random Out of These Numbers. What is the Probability that this Number Has the Same Digits?

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Question

Three digit numbers are formed using the digits 0, 2, 4, 6, 8. A number is chosen at random out of these numbers. What is the probability that this number has the same digits?

Options

  • \[\frac{1}{16}\]

     

  • \[\frac{16}{25}\]

     

  • \[\frac{1}{645}\]

     

  • \[\frac{1}{25}\]

     

MCQ
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Solution

The given digits are 0, 2, 4, 6, 8.

____ ____ ____
Hundreds Tens Ones
Now, there are 4 ways to fill the hundreds place (0 cannot occupy the hundreds place), 5 ways to fill the tens place and 5 ways to fill the ones place.
Total number of 3 digit numbers formed using the given digits = 4 × 5 × 5 = 100
The three digit numbers formed using given digits that have the same digits are 222, 444, 666 and 888.
Number of 3 digit numbers that have the same digits = 4
∴ P(three digit number formed has the same digits) = \[\frac{\text{ Number of 3 digit numbers that have the same digits} }{\text{ Total number of 3 digit numbers formed using the given digits} } = \frac{4}{100} = \frac{1}{25}\]

 

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Chapter 33: Probability - Exercise 33.6 [Page 73]

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R.D. Sharma Mathematics [English] Class 11
Chapter 33 Probability
Exercise 33.6 | Q 40 | Page 73
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