Question

Three coins are tossed simultaneously the probability of getting atleast two heads is ______.

Options

• \[\frac{1}{2}\]

• \[\frac{1}{3}\]

• \[\frac{1}{4}\]

• \[\frac{3}{8}\]

Answer 1

Three coins are tossed simultaneously the probability of getting atleast two heads is \[\underline{\boldsymbol{\frac{1}{2}}}\]. 

Explanation: 

When three coins are tossed together; the possible outcomes are:

HHH, HHT, HTH, THH, HTT, THT, TTH and TTT.

i.e., the total number of possible outcomes = 8

Favorable outcomes for getting atleast two heads are: HHH, HHT, HTH, THH.

i.e., the number of favorable outcomes = 4

P(getting atleast two heads) = \[\frac{\text{No. of favourable outcomes}}{\text{Total no. of possible outcomes}} = \frac{4}{8} = \frac{1}{2}\]