Advertisements
Advertisements
Question
There is a square field whose side is 44m. A square flower bed is prepared in its centre leaving a gravel path all round the flower bed. The total cost of laying the flower bed and graving the path at Rs 2. 75 and Rs. 1.5 per square metre, respectively, is Rs 4,904. Find the width of the gravel path.
Advertisements
Solution
Let the side of flower bed be a and that of gravel path be b.
Then a + 2b = 44 (as 44 is overall size of field and it contains side of flower bed and double side of gravel path) .... (i)
Area of Flower bed = a2
Area of Gravel path = Area of Square - Area of flower bed = 44 x 44 - a2
⇒ Area of Gravel path = 1936 - a2
Cost of laying flower bed + Gravel path = Area x cost of laying per sq.m
⇒ 4904 = (a2 x 2.75) + (1936 - a2) x 1.5
⇒ 4904 = 2.75a2 -1.5 a2 + 2904
⇒ 1.25 a2 = 2000
⇒ a2 = 1600, Hence a = 40.
Hence gravel path width = `(44 - 40)/2` m = 2 m
APPEARS IN
RELATED QUESTIONS
Find two consecutive positive integers, sum of whose squares is 365.
If the list price of a toy is reduced by Rs. 2, a person can buy 2 toys more for Rs. 360. Find the original price of the toy.
The sum of the squares of two consecutive positive even numbers is 452. Find the numbers.
One of the roots of equation 5m2 + 2m + k = 0 is `(-7)/5` Complete the following activity to find the value of 'k'.
Solve the following quadratic equations by factorization:
\[3\left( \frac{7x + 1}{5x - 3} \right) - 4\left( \frac{5x - 3}{7x + 1} \right) = 11; x \neq \frac{3}{5}, - \frac{1}{7}\]
Find the values of k for which the roots are real and equal in each of the following equation:
\[4 x^2 + px + 3 = 0\]
Write the number of zeroes in the end of a number whose prime factorization is 22 × 53 × 32 × 17.
One fourth of a herd of camels was seen in the forest. Twice the square root of the herd had gone to mountains and the remaining 15 camels were seen on the bank of a river. Find the total number of camels.
Solve the following equation by factorization
21x2 – 8x – 4 = 0
Find three consecutive odd integers, the sum of whose squares is 83.
