English
Maharashtra State BoardSSC (English Medium) 9th Standard

There is a rectangular farm with length (2a2+3b2) metre and breadth (a2+b2) metre. The farmer used a square shaped plot of the farm to build a house.

Advertisements
Advertisements

Question

There is a rectangular farm with length `(2a^2 + 3b^2)` metre and breadth `(a^2 + b^2)` metre. The farmer used a square shaped plot of the farm to build a house. The side of the plot was `(a^2 -  b^2)` metre.
What is the area of the remaining part of the farm?

Sum
Advertisements

Solution

Lenght of the rectangular farm = (2a2 + 3b2) m

Breadth of the rectangular farm = (a2 + b2) m

The total area of the farm = Length of the rectangular farm × Breadth of the rectangular farm

= (2a2 + 3b2) × (a2 + b2)

= 2a2(a2 + b2) + 3b2(a2 + b2)

= 2a+ 2a2b+3a2b2 + 3b4 

= (2a4 + 5a2b2 + 3b2) sq.meter

Side of the square plot = (a2 − b2) meter.

Area of the square plot = (side)2

=  (a2 − b2)2

= a − 2a2b2 + b4

 Area of the remaining part of the farm = Total area of the farm − Area of the square plot

= (2a4 + 5a2b2 + 3b4) - (a4 − 2a2b2 + b4)

= 2a4 + 5a2b2 + 3b4 − a4 − 2a2b2 + b4 

= 2a4 − a+ 5a2b+ 2a2b2 + 3b4 − b

= a+ 7a2b+ 2b4

Thus, the area of the remaining part of the farm is (a4 + 7a2b+ 2b4) sq. meter.

shaalaa.com
Operations on Polynomials
  Is there an error in this question or solution?
Chapter 3: Polynomials - Practice Set 3.2 [Page 43]

APPEARS IN

Balbharati Mathematics 1 [English] Standard 9 Maharashtra State Board
Chapter 3 Polynomials
Practice Set 3.2 | Q (6) | Page 43

RELATED QUESTIONS

There are ‘a’ trees in the village Lat. If the number of trees increases every year by ‘b’, then how many trees will there be after ‘x’ years?


The tens and units place of a two digit number is m and n respectively. Write the polynomial which represents the two digit number.


Add the given polynomials.

`x^3 - 2x^2 - 9 ;  5x^3 + 2x + 9`


Add the given polynomial.

`-7m^4 +5m^3 + sqrt2 ;   5m^4 - 3m^3 + 2m^2 + 3m - 6`


Add the given polynomial.

`2y^2 + 7y + 5  ;  3y + 9  ;  3y^2 - 4y - 3`


Subtract the second polynomial from the first.

`x^2 - 9x + sqrt 3  ;  -19x + sqrt 3 +7x^2`


Subtract the second polynomial from the first.

`2ab^2 + 3a^2b - 4ab ; 3ab - 8ab^2 + 2a^2b`


Multiply the given polynomial.

`2x  ;  x^2 - 2x - 1`


Divide first polynomial by second polynomial and write the answer in the form ‘Dividend = Divisor × Quotient + Remainder’.

`x^3 - 64 ; x - 4`


Divide first polynomial by second polynomial and write the answer in the form ‘Dividend = Divisor × Quotient + Remainder’.

`5x^5 + 4x^4 - 3x^3 + 2x^2 +2;x^2-x`


Add the following polynomial.

`7x^4 - 2x^3 + x + 10 ; 3x^4 + 15x^3 + 9x^2 - 8x + 2`


Add the following polynomial.

`3p^3q+ 2p^2q + 7; 2p^2q + 4pq - 2p^3q`


Subtract the second polynomial from the first.

`5x^2 - 2y + 9 ; 3x^2 + 5y - 7`


Multiply the following polynomial.

`(m^3 - 2m + 3)(m^4 - 2m^2 + 3m + 2)`


Multiply the following polynomial.

`(5m^3 - 2) (m^2 - m + 3)`


Simplify.

(8m2 + 3m − 6) − (9m − 7) + (3m2 − 2m + 4)


Which polynomial is to be added to 4m + 2n + 3 to get the polynomial 6m + 3n + 10?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×