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Question
There are two examination rooms A and B. If 10 candidates are sent from A to B, the number of students in each room is same. If 20 candidates are sent from B to A, the number of students in A is double the number of students in B. Find the number of students in each room.
Numerical
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Solution
Given: Let the number of students in rooms A and B be x and y respectively.
Step-wise calculation:
1. After sending 10 from A to B they become equal:
x – 10 = y + 10
⇒ x – y = 20
2. After sending 20 from B to A, A has double B:
x + 20 = 2(y – 20)
⇒ x + 20 = 2y – 40
⇒ x – 2y = –60
3. Solve the system: From (1) x = y + 20.
Substitute into (2): (y + 20) – 2y = –60
–y + 20 = –60
–y = –80
⇒ y = 80
Then x = y + 20
= 80 + 20
= 100
Room A has 100 students and Room B has 80 students.
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