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Question
There are 5 teachers and 20 students. Out of them a committee of 2 teachers and 3 students is to be formed. Find the number of ways in which this can be done. Further find in how many of these committees a particular student is excluded?
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Solution
The number of teachers = 5
Number of students = 20
The number of ways of selecting 2 teachers from 5 teachers is
= 5C2 ways.
= `(5!)/(2! xx (5 - 2)!)`
= `(5!)/(2! xx 3!)`
= `(5 xx 4 xx 3!)/(2! xx 3!)`
= `(5 xx 4)/(2 xx 1)`
= 10 ways
The number of ways of selecting 3 students from 20 students is
= 20C3
= `(20!)/(3! xx (20 - 3)!)`
= `(20!)/(3! xx 17!)`
= `(20 xx 19 xx 18 xx 17!)/(3! xx 17!)`
= `(20 xx 19 xx 18)/(3 xx 2 xx 1)`
= 20 × 19 × 3
= 1140 ways
∴ The total number of selection of the committees with 2 teachers and 5 students is
= 10 × 1140
= 11400
A particular student is excluded.
The number of ways of selecting 2 teachers from 5 teachers is
= 5C2
= `(5!)/(2! xx (5 - 2)!)`
= `(5!)/(2! xx 3!)`
= `(5 xx 4 xx 3!)/(2! xx 3!)`
= `(5 xx 4)/(2 xx 1)`
= 5 × 2
= 10
A particular student is excluded
∴ The number of remaining students = 19
Number of ways of selecting 3 students from 19 students
= 19C3
= `(19!)/(3! xx (19 - 3)!)`
= `(19!)/(3! xx 16!)`
= `(19 xx 18 xx 17 xx 16!)/(3! xx 16!)`
= `(19 xx 18 xx 17)/(3!)`
= `(19 xx 18 xx 17)/(3 xx 2 xx 1)`
= 19 × 3 × 17
= 969
∴ The required number of committees
= 10 × 969
= 9690
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