Advertisements
Advertisements
Question
The wheel of a bullock cart has a diameter of 1.4 m. How many rotations will the wheel complete as the cart travels 1.1 km?
Advertisements
Solution
Diameter of the wheel, d = 1.4 m
Circumference, c = πd
= `22/7xx1.4`
= 22 × 0.2
= 4.4 m
Distance covered in 1 rotation = circumference of the wheel = 4.4m
∴ Total number of rotations taken by wheel = `"total distance"/"circumference"`
= `(1.1 xx 1000)/4.4`
= `(11 xx 1000)/44`
= `11000/44`
= 250
Hence, the wheel of the bullock cart will complete 250 rotations as the cart travels 1.1 km.
RELATED QUESTIONS
In PSR, RTQ and PAQ are three semicircles of diameters 10 cm, 3 cm and 7 cm respectively. Find the perimeter of the shaded region. [Use π=3.14]
The inner circumference of a circular track is 220 m. The track is 7m wide everywhere. Calculate the cost of putting up a fence along the outer circle at the rate of j – 2 per metre. (Use π = 22/7)
Find the circumference of the inner and the outer circles, shown in the adjoining figure? (Take π = 3.14)
In circle of radius 6cm, chord of length 10 cm makes an angle of 110° at the centre of circle find Circumference of the circle
Find the diameter of the circle whose area is equal to the sum of the areas of two circles having radii 4 cm and 3 cm.
In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. The length of the arc is
Find the curved surface area , the total surface area and the volume of a cone if its :
Height = 8 cm , diameter = 12 cm
The circumference of a circle is 440 cm. Find its radius and diameter. (Take π = `22/7`)
The inner circumference of a circular track is 264 m and the width of the track is 7 m. Find:
(i) the radius of the inner track.
(ii) the radius of the outer circumference.
(iii) the length of the outer circumference.
(iv) the cost of fencing the outer circumference at the rate of ₹50 per m.
Sudhanshu divides a circular disc of radius 7 cm in two equal parts. What is the perimeter of each semicircular shape disc? (Use π = `22/7`)
