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Question
The wavelength of light in a medium ‘M’ is 900 nm. If the wave enters a medium ‘N’ of refractive index `4/3`, then its wavelength is:
Options
675 nm
650 nm
695 nm
700 nm.
MCQ
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Solution
675 nm
Explanation:
The frequency of light remains unchanged during refraction.
Taking the given refractive index as that of medium N,
$$\lambda_N = \dfrac{\lambda_M}{\mu_N}$$
$$= \dfrac{900\ \mathrm{nm}}{4/3}$$
= 675 nm
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