Question

The volume of the frustum of a cone is `1/3 pih[r_1^2 + r_2^2 - r_1r_2]`, where h is vertical height of the frustum and r₁, r₂ are the radii of the ends.

Options

• True

• False

Answer 1

This statement is False.

Explanation:

Since, the volume of the frustum of a cone is `1/3 pi"h"["r"_1^2 + "r"_2^2 + "r"_1"r"_2]`, where h is vertical height of the frustum and r₁, r₂ are the radii of the ends.