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Question
The vector form of the torque on a magnetic dipole in a uniform magnetic field is:
Options
\[\vec{\tau} = \vec{B} \times \vec{m}\]
\[\vec{\tau} = mB\cos\theta\]
\[\vec{\tau} = \vec{m} \cdot \vec{B}\]
\[\vec{\tau} = \vec{m} \times \vec{B}\]
MCQ
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Solution
The torque on a magnetic dipole is the cross product \[\vec{\tau} = \vec{m} \times \vec{B}\], where \[\vec{m} = NI\vec{A}\]. Its magnitude is \[mB\sin\theta = NIAB\sin\theta\], matching the scalar expression for the torque.
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