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The vector equation of the line x-53=y+47=z-62 is rijkijkr→=5i^-4j^+6k^+λ(3i^+7j^+2k^).

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Question

The vector equation of the line `(x - 5)/3 = (y + 4)/7 = (z - 6)/2` is `vec"r" = 5hat"i" - 4hat"j" + 6hat"k" + lambda(3hat"i" + 7hat"j" + 2hat"k")`.

Options

  • True

  • False

MCQ
True or False
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Solution

This statement is True.

Explanation:

The Cartesian form of the equation is `(x - 5)/3 = (y + 4)/7 = (z - 6)/2 = lambda`

∴ Here x1 = 5

y1 = – 4

z1 = 6,

a = 3

b = 7

c = 2

So, the vector equation is `vec"r" = (5hat"i" - 4hat"j" + 6hat"k") + lambda(3hat"i" + 7hat"j" + 2hat"k")`

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Chapter 11: Three Dimensional Geometry - Exercise [Page 239]

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NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 11 Three Dimensional Geometry
Exercise | Q 47 | Page 239
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