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Question
The value of tan2 (sec–12) + cot2 (cosec–13) is ______.
Options
5
11
13
15
MCQ
Fill in the Blanks
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Solution
The value of tan2 (sec–12) + cot2 (cosec–13) is 11.
Explanation:
tan2 (sec–12) + cot2 (cosec–13) = sec2 (sec–12) – 1 + cosec2 (cosec–13) – 1
= 22 × 1 + 32 – 2
= 11.
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