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Question
The use of a radial magnetic field, in which \(\sin\theta = 1\) at all positions, produces a galvanometer scale deflection that is:
Options
linear and directly proportional to the current
quadratic in the current
independent of the current
inversely proportional to the current
MCQ
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Solution
Because \(\sin\theta = 1\) everywhere, the deflecting torque \(\tau = NIAB\) is balanced by the restoring torque \(C\phi\), giving \(\phi \propto I\). This makes the scale linear and uniform.
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