English

The two waves are represented by Y1 = t10-2sin[50t+x25+0.3]m and Y2 = t10-2cos[50t+x25]m where x is in metre and time in second. The phase difference between the two waves is nearly _________.

Advertisements
Advertisements

Question

The two waves are represented by Y1 = `10-2 sin [50"t" + x/25 + 0.3]`m and Y2 = `10^-2 cos [50"t" + x/25]`m where x is in metre and time in second. The phase difference between the two waves is nearly _________.

Options

  • 1.22 rad

  • 1.05 rad

  • 1.15 rad

  • 1.27 rad

MCQ
Fill in the Blanks
Advertisements

Solution

The two waves are represented by Y1 = `10-2 sin [50"t" + x/25 + 0.3]`m and Y2 = `10^-2 cos [50"t" + x/25]`m where x is in metre and time in second. The phase difference between the two waves is nearly 1.27 rad.

Explanation:

Y1 = `10-2 sin [50"t" + x/25 + 0.3]`m

Y2 = `10^-2 cos [50"t" + x/25]`m

∴ Phase difference between the two waves is

`phi = pi/2 - 0.3 = 1.57 - 0.3 = 1.27`rad

shaalaa.com
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×