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Question
The total marks scored by two students Sathya and Vidhya in 5 subjects are 460 and 480 with standard deviation of 4.6 and 2.4 respectively. Who is more consistent in performance?
Sum
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Solution
Total marks scored by Sathya = 460
Total marks scored by Vidhya = 480
Number of subjects = 5
Mean marks of sathya = `460/5`
`bar(x)` = 92%
Given standard deviation, (σ) = 4.6
Coefficient of variation = `sigma/bar(x) xx 100%`
= `4.6/92 xx 100%`
= `460/92`
= 5%
Mean marks of vidhya = `480/5` = 96%
Given Standard deviation (σ) = 2.4
Coefficient of variation = `2.4/96 xx 100`
= `240/96`
= 2.5%
CV1 > CV2
Vidhya coefficient of variation is less than Sathya.
Vidhya is more consistent.
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