Question

The total marks scored by two students Sathya and Vidhya in 5 subjects are 460 and 480 with standard deviation of 4.6 and 2.4 respectively. Who is more consistent in performance?

Answer 1

Total marks scored by Sathya = 460

Total marks scored by Vidhya = 480

Number of subjects = 5

Mean marks of sathya = `460/5`

`bar(x)` = 92%

Given standard deviation, (σ) = 4.6

Coefficient of variation = `sigma/bar(x) xx 100%`

= `4.6/92 xx 100%`

= `460/92`

= 5%

Mean marks of vidhya = `480/5` = 96%

Given Standard deviation (σ) = 2.4

Coefficient of variation = `2.4/96 xx 100`

= `240/96`

= 2.5%

CV₁ > CV₂

Vidhya coefficient of variation is less than Sathya.

Vidhya is more consistent.