Advertisements
Advertisements
Question
The temperature of a uniform rod of length L having a coefficient of linear expansion αL is changed by ∆T. Calculate the new moment of inertia of the uniform rod about the axis passing through its center and perpendicular to an axis of the rod.
Advertisements
Solution
Moment of inertia of a uniform rod of mass and length l about its perpendicular bisector. Moment of inertia of the rod
I = `1/12"ML"^2`
Increase in length of the rod when temperature is increased by ∆T, is given by
L’ = L(1 + αL∆T)
I’ = `"ML’"^2/12 = "M"/12"L"^2`(1 + αL∆T)2
I’ = I(1 + αL∆T)2
APPEARS IN
RELATED QUESTIONS
Choose the correct option.
If two temperatures differ by 25° C on Celsius scale, the difference in temperature on Fahrenheit scale is
Choose the correct option.
If α, β and γ are coefficients of linear, area l and volume expansion of a solid then
Define specific heat capacity.
Give the expression for linear thermal expansion.
Define latent heat capacity.
Discuss the ideal gas laws.
Explain in detail the thermal expansion.
Another name for thermal energy is ______
What does the temperature of a body tell us?
Why is the sense of touch not sufficient to measure temperature scientifically?
