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The tangent to a circle of radius 8 cm from an external point P is of length 6 cm. Find the distance of P from the nearest point to the circle. - Mathematics

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Question

The tangent to a circle of radius 8 cm from an external point P is of length 6 cm. Find the distance of P from the nearest point to the circle.

Sum
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Solution

Given

Radius of circle = 8 cm.

Length of tangent from point P = 6 cm.

PA is tangent, O is centre, A is point of tangency.

Need to find: the distance of P from the nearest point on the circle.

That nearest point is the point where the line PO meets the circle.

Step 1: Use the tangent–radius right-angle property.

Radius to the point of tangency is perpendicular to the tangent:

OA ⊥ PA

Thus, triangle POA is right-angled at A.

Step 2: Apply Pythagoras

PO2 = PA2 + OA2

PO2 = 62 + 82

PO2 = 36 + 64 = 100

PO = 10 cm

Step 3: Distance from P to the nearest point on the circle.

The nearest point lies on the line PO.
Distance = PO − radius:

Required distance = 10 − 8 = 2 cm

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Chapter 15: Circles - Exercise 15B [Page 353]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 15 Circles
Exercise 15B | Q 3. | Page 353
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